United States presidential election in Montana, 1996
The 1996 United States presidential election in Montana took place on November 5, 1996. Voters chose 3 representatives, or electors to the Electoral College, who voted for President and Vice President.
Montana voted for Senate Majority Leader Bob Dole over President Bill Clinton by a slim margin of 2.88%.[1] Billionaire businessman Ross Perot (Reform Party of the United States of America-TX) finished in third with 13.56% of the popular vote in Montana.[2]
Results
References
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