Oxford Township, Delaware County, Ohio

Oxford Township, Delaware County, Ohio
Township

Fields in the township's far southwest

Location of Oxford Township in Delaware County
Coordinates: 40°24′10″N 82°58′51″W / 40.40278°N 82.98083°W / 40.40278; -82.98083Coordinates: 40°24′10″N 82°58′51″W / 40.40278°N 82.98083°W / 40.40278; -82.98083
Country United States
State Ohio
County Delaware
Area
  Total 19.41 sq mi (50.28 km2)
  Land 19.41 sq mi (50.27 km2)
  Water 0.004 sq mi (0.01 km2)
Elevation[1] 968 ft (295 m)
Population (2010)
  Total 987
  Density 51/sq mi (19.6/km2)
Time zone Eastern (EST) (UTC-5)
  Summer (DST) EDT (UTC-4)
FIPS code 39-59262[2]
GNIS feature ID 1086053[1]

Oxford Township is one of the eighteen townships of Delaware County, Ohio, United States. As of the 2010 census the population was 987,[3] up from 854 at the 2000 census.[4]

Geography

Located in the northern part of the county, it borders the following townships:

The village of Ashley occupies part of northeastern Oxford Township.

Name and history

Oxford Township was founded in 1815.[5]

It is one of six Oxford Townships statewide.[6]

Government

The township is governed by a three-member board of trustees, who are elected in November of odd-numbered years to a four-year term beginning on the following January 1. Two are elected in the year after the presidential election and one is elected in the year before it. There is also an elected township fiscal officer,[7] who serves a four-year term beginning on April 1 of the year after the election, which is held in November of the year before the presidential election. Vacancies in the fiscal officership or on the board of trustees are filled by the remaining trustees.

References

This article is issued from Wikipedia - version of the 11/3/2016. The text is available under the Creative Commons Attribution/Share Alike but additional terms may apply for the media files.