Chorula
| Chorula | |
|---|---|
| Village | |
|
Church | |
  Chorula | |
| Coordinates: 50°32′N 17°58′E / 50.533°N 17.967°E | |
| Country |
 Poland |
| Voivodeship | Opole |
| County | Krapkowice |
| Gmina | Gogolin |
| Population | 640 |
| Website | http://www.chorula.pl/ |
Chorula [xɔˈrula] (German Chorulla) is a village in the administrative district of Gmina Gogolin, within Krapkowice County, Opole Voivodeship, in south-western Poland.[1] It lies approximately 7 kilometres (4 mi) north-west of Gogolin, 8 km (5 mi) north of Krapkowice, and 15 km (9 mi) south of the regional capital Opole.
Before 1945 the area was part of Germany (see Territorial changes of Poland after World War II).
The village has a population of 440.
References
| Town and seat |  | |
|---|---|---|
| Villages | ||
Coordinates: 50°32′N 17°58′E / 50.533°N 17.967°E
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